Energy radiated by a transmitter – Rankers Physics

Power: Practice Problem & Solution

The energy that will be ideally radiated by a $100\text{ kW}$ transmitter in $1\text{ hour}$ is: (2022)
$1 \times 10^5\text{ J}$
$36 \times 10^7\text{ J}$
$36 \times 10^4\text{ J}$
$36 \times 10^5\text{ J}$

Solution Explained:

To solve this problem, we apply the core principles of Power. Understanding the underlying formula is key to arriving at the correct answer below:

Energy is given by $E = P \times t$. Here, power $P = 100\text{ kW} = 10^5\text{ W}$ and time $t = 1\text{ hour} = 3600\text{ s}$. Thus, $E = 10^5 \times 3600 = 3.6 \times 10^8\text{ J} = 36 \times 10^7\text{ J}$.

Leave a Reply

Your email address will not be published. Required fields are marked *

Similar Practice Questions

Explore conceptually related problems to test your knowledge.

1. A pump motor is used to deliver water at a certain rate from a given pipe. To obtain "2" time water from the same pipe in the same time, the amount to which the power of the motor should be increased is :
2. When a spring is subjected to \(4\text{ N}\) force its length is \(a\text{ metre}\). And if \(5\text{ N}\) is applied length is \(b\text{ metre}\). If \(9\text{ N}\) is applied length is: (1999)
3. A particle of mass $m$ is driven by a machine that delivers a constant power $k$ watts. If the particle starts from rest the force on the particle at time $t$ is: (2015)
4. Assertion (A): A particle is rotated in a vertical circle with the help of a string. Work done by tension in the string on particle is zero. Reason (R): Tension is always perpendicular to instantaneous velocity.
5. A body of mass $3\text{ kg}$ is under a constant force which causes a displacement $s$ in meters in it, given by the relation $s = \frac{1}{3} t^2$, where $t$ is in $s$. Work done by the force in $2\text{ s}$ is: (2006)