Waves and its Characteristics: Practice Problem & Solution
In a guitar, two strings \(A\) and \(B\) are slightly out of tune and produce 3 beats per second. When tension in \(B\) is slightly reduced, both the strings come in unison. If frequency of \(A\) is \(630\text{ Hz}\), then original frequency of \(B\) was
Short Solution (Best for NEET):
To solve this problem, we apply the core principles of Waves and its Characteristics. Understanding the underlying formula is key to arriving at the correct answer below:
Beats = \(|f_A - f_B| = 3\text{ Hz}\). Since reducing tension in B decreases its frequency to unison (630 Hz), B's initial frequency must have been higher than 630 Hz. Thus, \(f_B = 633\text{ Hz}\).
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