Standing Wave in String and Organ Pipe: Practice Problem & Solution

Solution Explained:

To solve this problem, we apply the core principles of Standing Wave in String and Organ Pipe. Understanding the underlying formula is key to arriving at the correct answer below:

Since frequency $f \propto 1/l$, the lengths will be in the ratio $1/1 : 1/2 : 1/3 = 6:3:2$. The sum of the ratios is 11. Lengths are $60 \text{ cm}$, $30 \text{ cm}$, and $20 \text{ cm}$. The bridges should be placed at $60 \text{ cm}$ and $60 + 30 = 90 \text{ cm}$ from A.