Rankers Physics

Standing Wave in String and Organ Pipe: Practice Problem & Solution

An air column, closed at one end and open at the other, resonates with a tuning fork when the smallest length of the column is $50 \text{ cm}$. The next larger length of the column resonating with the same tuning fork is: (2016-I)
$66.7 \text{ cm}$
$100 \text{ cm}$
$150 \text{ cm}$
$200 \text{ cm}$

Solution Explained:

To solve this problem, we apply the core principles of Standing Wave in String and Organ Pipe. Understanding the underlying formula is key to arriving at the correct answer below:

Smallest length $L_1 = \lambda/4 = 50 \text{ cm}$. Next resonating length $L_2 = 3\lambda/4 = 3 L_1 = 3 \times 50 = 150 \text{ cm}$.

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