Waves and its Characteristics: Practice Problem & Solution

Solution Explained:

To solve this problem, we apply the core principles of Waves and its Characteristics. Understanding the underlying formula is key to arriving at the correct answer below:

Since $v \propto \sqrt{T}$, to double the speed, temperature must be quadrupled. $T_1 = 273 + 27 = 300 \text{ K}$. $T_2 = 4 \times 300 = 1200 \text{ K}$, which is $1200 - 273 = 927^{\circ}\text{C}$.