Waves and its Characteristics: Practice Problem & Solution
Two points are located at a distance of $10text{ m}$ and $15text{ m}$ from the source of oscillation. The period of oscillation is $0.05text{ sec}$ and the velocity of the wave is $300text{ m/sec}$. What is the phase difference between the oscillations of two points? (2008)
Solution Explained:
To solve this problem, we apply the core principles of Waves and its Characteristics. Understanding the underlying formula is key to arriving at the correct answer below:
Frequency $f = 1/T = 1/0.05 = 20text{ Hz}$. Wavelength $\lambda = v/f = 300/20 = 15text{ m}$. The path difference is $\Delta x = 15 - 10 = 5text{ m}$. The phase difference is $\Delta\phi = (2\pi/\lambda)\Delta x = (2\pi/15) \times 5 = 2\pi/3$.
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