Rankers Physics

Young's Double Slit Experiment: Practice Problem & Solution

In a standard Young's double slit setup, we get 60 fringes on a section of screen with monochromatic light of wavelength 4000 Å. If we use monochromatic light of wavelength 6000Å, then the number of fringes that would be obtained in the same section is
60
90
40
1.5

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Similar Practice Questions

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1. Assertion (A): If width of one of the slit in YDSE is slightly increased, then maximum and minimum both Intensity will increase. Reason (R): Intensity reaching from that slit on screen will slightly increase.
2. In a double slit experiment, the two slits are 1 mm apart and the screen is placed 1 m away. A monochromatic light of wavelength 500 nm is used. What will be the width of each slit for obtaining ten maxima of double slit within the central maxima of single slit pattern? (2015)
3. Assertion (A): In YDSE central maxima means the maxima formed with zero optical path difference. It may be formed anywhere on the screen. Reason (R): In an interference pattern, whatever energy disappears at the minimum, appears at the maximum.  
4. In Young's double slit experiment, one of the slit is wider than other, so that the amplitude of the light from one slit is double of that from other slit. If Im be the maximum intensity, the resultant intensity I when they interfere at phase difference Φ is given by :
5. Assertion (A): In the double slit experiment, if one of the slit is closed, no fringe pattern will be observed on the screen. Reason (R): In interference, phenomenon of diffraction is also included.