Rankers Physics

Diffraction: Practice Problem & Solution

In the far field diffraction pattern of a single slit under polychromatic illumination, the first minima with the wavelength λ1 is found to be coincident with the third maximum at λ2. So :
3λ1 = 0.3λ2
3λ1 = λ2
λ1 = 3.5λ2
0.3λ1 = 3λ2

No solution provided for this question.

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1. Assertion (A): Light is diffracted around the edges of obstacles and it bend such a way which is not easily observed. Reason (R): The wavelength of light is very small.  
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