Young's Double Slit Experiment: Practice Problem & Solution

Solution Explained:

To solve this problem, we apply the core principles of Young's Double Slit Experiment. Understanding the underlying formula is key to arriving at the correct answer below:

Ratio of slit widths $W_1/W_2 = I_1/I_2 = 1/25$. Amplitudes ratio $a_1/a_2 = \sqrt{1/25} = 1/5$. The intensity ratio is $\frac{I_{max}}{I_{min}} = \left(\frac{a_1+a_2}{a_1-a_2}\right)^2 = \left(\frac{1+5}{1-5}\right)^2 = \left(\frac{6}{-4}\right)^2 = \frac{36}{16} = \frac{9}{4}$.