Rankers Physics

Young's Double Slit Experiment: Practice Problem & Solution

In Young's double slit experiment, if the separation between coherent sources is halved and the distance of the screen from the coherent sources is doubled, then the fringe width becomes: (2020)
Half
Four times
One-fourth
Double

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Young's Double Slit Experiment. Understanding the underlying formula is key to arriving at the correct answer below:

Fringe width is given by $beta = frac{lambda D}{d}$. When $D' = 2D$ and $d' = d/2$, the new fringe width is $beta' = frac{lambda (2D)}{(d/2)} = 4 frac{lambda D}{d} = 4beta$. It becomes four times the original.

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