Least count of vernier callipers – Rankers Physics

Vernier Calliper: Practice Problem & Solution

The vernier scale of a callipers is divided into 20 divisions which coincide with 18 main scale divisions. Each main scale division is 0.2 mm. The least count of the instrument is
0.2 mm
0.02 mm
0.1 mm
0.01 mm

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Vernier Calliper. Understanding the underlying formula is key to arriving at the correct answer below:

Least count (LC) is given by \(text{LC} = 1text{ MSD} - 1text{ VSD}\). Since 20 VSD = 18 MSD, we have \(1text{ VSD} = 0.9text{ MSD}\). Thus, \(text{LC} = 0.1text{ MSD} = 0.1 times 0.2text{ mm} = 0.02text{ mm}\).

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