Tension in Lift Cable (Upward Acceleration) – Rankers Physics

Uncategorized: Practice Problem & Solution

A lift of mass \(1000 text{ kg}\) which is moving with acceleration of \(1 text{ m s}^{-2}\) in upward direction, then the tension developed in string which is connected to lift is: (2002)
\(9800 text{ N}\)
\(10,800 text{ N}\)
\(11000 text{ N}\)
\(10.000 text{ N}\)

Solution Explained:

To solve this problem, we apply the core principles of Uncategorized. Understanding the underlying formula is key to arriving at the correct answer below:

Mass \(m = 1000 text{ kg}\), acceleration \(a = 1 text{ m/s}^2\) upwards. Using \(g = 9.8 text{ m/s}^2\).Tension \(T = m(g+a) = 1000(9.8 + 1) = 1000(10.8)\).Thus, \(T = 10800 text{ N}\).

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