Uncategorized: Practice Problem & Solution
A block of mass \(m\) is placed on a smooth wedge of inclination \(theta\). The whole system is accelerated horizontally so that the block does not slip on the wedge. The force exerted by the wedge on the block (\(g\) is acceleration due to gravity) will be: (2004)
Short Solution (Best for NEET):
To solve this problem, we apply the core principles of Uncategorized. Understanding the underlying formula is key to arriving at the correct answer below:
For no slipping, horizontal acceleration \(a = g tantheta\).The normal force \(N\) must balance the effective weight perpendicular to the incline.This gives \(N = sqrt{(mg)^2 + (ma)^2}\) if the forces are orthogonal.More correctly, resolving forces perpendicular to the incline, \(N - mg costheta - ma sintheta = 0\).Substituting \(a = g tantheta\), we get \(N = mg/costheta\).
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