Uncategorized: Practice Problem & Solution
Velocity of sound in air is $320text{ m/s}$. If frequency of $1^{text{st}}$ overtone of a closed organ pipe is $480text{ Hz}$, then the length of the organ pipe is
Solution Explained:
To solve this problem, we apply the core principles of Uncategorized. Understanding the underlying formula is key to arriving at the correct answer below:
For a closed organ pipe, the $1^{text{st}}$ overtone frequency is $f = frac{3v}{4L}$. Substituting the values: $480 = frac{3 times 320}{4L} implies L = 0.5text{ m} = 50text{ cm}$.
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