Impulse on a Wall – Rankers Physics

Uncategorized: Practice Problem & Solution

A body of mass \( m \) hits normally a rigid wall with velocity \( v \) and bounces back with the same velocity. The impulse experienced by the body is: (2011 Pre)
\( mv \)
\( 1.5 mv \)
\( 2 mv \)
Zero

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Uncategorized. Understanding the underlying formula is key to arriving at the correct answer below:

Impulse is the change in momentum. Initial momentum \( P_i = mv \). Final momentum \( P_f = -mv \) (opposite direction). Impulse \( J = P_f - P_i = -mv - mv = -2mv \). Magnitude is \( 2mv \).

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