Uncategorized: Practice Problem & Solution
A cricketer catches a ball of mass \(150text{ gm}\) in \(0.1text{ second}\) moving with speed \(20text{ ms}^{-1}\), then he experiences force of: (2001)
Solution Explained:
To solve this problem, we apply the core principles of Uncategorized. Understanding the underlying formula is key to arriving at the correct answer below:
Force is the rate of change of momentum: \(F = frac{Delta p}{Delta t} = frac{m(v-u)}{Delta t}\). Given \(m = 150text{ gm} = 0.15text{ kg}\), \(u = 20text{ m/s}\), \(v = 0text{ m/s}\), \(Delta t = 0.1text{ s}\). So, \(F = frac{0.15 times (0 - 20)}{0.1} = frac{-3}{0.1} = -30text{ N}\). The magnitude of the force is \(30text{ N}\).
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