Rankers Physics

Uncategorized: Practice Problem & Solution

A particle executing simple harmonic motion of amplitude $5 \text{ cm}$ has maximum speed of $31.4 \text{ cm/s}$. The frequency of its oscillation is: (2005)
$2 \text{ Hz}$
$1.5 \text{ Hz}$
$0.5 \text{ Hz}$
$1 \text{ Hz}$

Solution Explained:

To solve this problem, we apply the core principles of Uncategorized. Understanding the underlying formula is key to arriving at the correct answer below:

$v_{\text{max}} = A\omega = A(2\pi f)$.\nSubstituting the given values, $31.4 = 5 \times 2 \times 3.14 \times f$.\nSolving this, we get $f = 1 \text{ Hz}$.

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