Uncategorized: Practice Problem & Solution
A monoatomic gas at pressure $P_1$ and $V_1$ is compressed adiabatically to $\frac{1}{8}\text{th}$ its original volume. What is the final pressure of the gas? (2010 Mains)
Solution Explained:
To solve this problem, we apply the core principles of Uncategorized. Understanding the underlying formula is key to arriving at the correct answer below:
For an adiabatic process, $P_1 V_1^\gamma = P_2 V_2^\gamma$. For a monoatomic gas, $\gamma = 5/3$. Substituting $V_2 = V_1 / 8$, we find $P_2 = P_1 (8)^{5/3} = 32 P_1$.
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