Thermodynamics: Practice Problem & Solution
110 J of heat is added to a gaseous system whose internal energy is increased by 40 J then amount of external work done is
Solution Explained:
To solve this problem, we apply the core principles of Thermodynamics. Understanding the underlying formula is key to arriving at the correct answer below:
According to the first law of thermodynamics, \(\Delta Q = \Delta U + W\). Substituting the values, \(110\text{ J} = 40\text{ J} + W \Rightarrow W = 70\text{ J}\).
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