Translational Kinetic Energy of Ideal Gases – Rankers Physics

Kinetic Theory of Gases: Practice Problem & Solution

Assertion (A): The average translational kinetic energy of the molecules in one mole of all ideal gases, at the same temperature is the same. Reason (R): The average kinetic energy of one mole of any ideal gas at temperature T is given by \( \frac{3}{2}RT \).  
Both (A) & (R) are true and the (R) is the correct explanation of the (A)
Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
(A) is true but (R) is false
Both (A) and (R) are false

Solution Explained:

To solve this problem, we apply the core principles of Kinetic Theory of Gases. Understanding the underlying formula is key to arriving at the correct answer below:

The average translational kinetic energy per mole for any ideal gas is \( \frac{3}{2}RT \), dependent only on T.


So (A) is true. The formula in (R) represents this average translational kinetic energy per mole. So (R) is true and correctly explains (A).

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