Thermodynamics: Practice Problem & Solution
'A' is a closed vessel of volume V and contains O2 at pressure P and temperature T. 'B' is another closed vessel of same volume and it contains H2 at same temperature and 2P pressure. Ratio of masses of O2 and H2 in vessel 'A' and 'B' is :
Solution Explained:
To solve this problem, we apply the core principles of Thermodynamics. Understanding the underlying formula is key to arriving at the correct answer below:
Using the ideal gas law \( PV = nRT \), we find the moles \( n \) in each vessel:
1. For vessel \( A \) with \( O_2 \):
\[
n_{\text{O}_2} = \frac{PV}{RT}
\]
2. For vessel \( B \) with \( H_2 \) at \( 2P \):
\[
n_{\text{H}_2} = \frac{2PV}{RT} = 2 \times \frac{PV}{RT}
\]
Now, the mass \( m = n \times \text{molar mass} \):
- Mass of \( O_2 \) in \( A = n_{\text{O}_2} \times 32 = \frac{PV}{RT} \times 32 \)
- Mass of \( H_2 \) in \( B = n_{\text{H}_2} \times 2 = 2 \times \frac{PV}{RT} \times 2 \)
So, the mass ratio is:
\[
\frac{\text{mass of } O_2}{\text{mass of } H_2} = \frac{\frac{PV}{RT} \times 32}{2 \times \frac{PV}{RT} \times 2} = \frac{32}{4} = 8:1
\]
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