Thermal Capacity of Aluminium – Rankers Physics

Calorimetry: Practice Problem & Solution

Thermal capacity of \(40\text{ g}\) of aluminium of specific heat \(0.2\text{ cal/(g }^\{circ}\text{C)}\) is
\(40\text{ cal/}^\{circ}\text{C}\)
\(160\text{ cal/}^\circ\text{C}\)
\(8\text{ cal/}^\circ\text{C}\)
\(200\text{ cal/}^\circ\text{C}\)

Solution Explained:

To solve this problem, we apply the core principles of Calorimetry. Understanding the underlying formula is key to arriving at the correct answer below:

Thermal capacity is given by the formula \(C = m \cdot s\). Substituting the values, \(C = 40\text{ g} \times 0.2\text{ cal/(g }^\circ\text{C)} = 8\text{ cal/}^\circ\text{C}\.

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