Ratio of Kinetic Energy of Gases – Rankers Physics

Kinetic Theory of Gases: Practice Problem & Solution

The ratio of total K.E of a molecule of Argon and Oxygen gas at 27°C is equal to:
3 : 5
3 : 2
2 : 3
5 : 7

Solution Explained:

To solve this problem, we apply the core principles of Kinetic Theory of Gases. Understanding the underlying formula is key to arriving at the correct answer below:

Total K.E. per molecule is \(\frac{f}{2}k_B T\). For monoatomic Argon, \(f=3\), and for diatomic Oxygen, \(f=5\). At equal temperature, the ratio of K.E. is \(3:5\).

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