Heat Transfer - Radiation: Practice Problem & Solution
A black body is at 727°C. It emits energy at a rate which is proportional to
Short Solution (Best for NEET):
To solve this problem, we apply the core principles of Heat Transfer - Radiation. Understanding the underlying formula is key to arriving at the correct answer below:
The energy emitted by a black body is proportional to the fourth power of its absolute temperature, as per Stefan-Boltzmann Law:
\[
P \propto T^4
\]
Step 1: Convert temperature to kelvins
The temperature of the black body is \(727^\circ C\), which is:
\[
T = 727 + 273 = 1000\,K
\]
Step 2: Apply Stefan-Boltzmann Law
Since the energy emitted is proportional to \(T^4\):
\[
P \propto (1000)^4
\]
Thus, the rate of energy emission is proportional to \((1000)^4\).
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