First Law of Thermodynamics for Isobaric Process – Rankers Physics

Thermodynamics: Practice Problem & Solution

For \(n\) mole of an ideal gas, the correct equation of \(1^{\text{st}}\) law of thermodynamics corresponding to isobaric process will be (symbols have their usual meanings)
\(Q = \Delta U + P\Delta V\)
\(Q = \Delta U + nR\Delta T\)
\(Q = \Delta U\)
Both (1) and (2)

Solution Explained:

To solve this problem, we apply the core principles of Thermodynamics. Understanding the underlying formula is key to arriving at the correct answer below:

According to the first law of thermodynamics, \(Q = \Delta U + W\). For an isobaric process, the work done is \(W = P\Delta V = nR\Delta T\). Therefore, both equations (1) and (2) are correct representation.

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