Cyclic Process Energy and Work – Rankers Physics

Thermodynamics: Practice Problem & Solution

Assertion (A): In cyclic process change in internal energy is zero. Reason (R): In cyclic process net work done is zero.  
Both (A) & (R) are true and the (R) is the correct explanation of the (A)
Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
(A) is true but (R) is false
Both (A) and (R) are false

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Thermodynamics. Understanding the underlying formula is key to arriving at the correct answer below:

For a cyclic process, the system returns to its initial state. Internal energy \( U \) is a state function, meaning its change depends only on the initial and final states. Since the initial and final states are the same in a cyclic process, the change in internal energy \( \Delta U \) is zero. Thus, Assertion (A) is true. According to the first law of thermodynamics, \( \Delta U = Q - W \). Since \( \Delta U = 0 \), it implies \( Q = W \). For a cyclic process, net work done \( W \) is generally not zero (e.g., heat engines operate in cycles to produce net work). Thus, Reason (R) is false. Therefore, (A) is true but (R) is false.

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