Absorptance from Reflectance and Transmittance – Rankers Physics

Heat Transfer - Radiation: Practice Problem & Solution

If transmittance of a surface is \(\frac{1}{7}\), reflectance is \(\frac{1}{8}\), then the absorptance of the surface will be
\(\frac{1}{9}\)
\(\frac{15}{56}\)
\(\frac{9}{56}\)
\(\frac{41}{56}\)

Solution Explained:

To solve this problem, we apply the core principles of Heat Transfer - Radiation. Understanding the underlying formula is key to arriving at the correct answer below:

By conservation of energy, the sum of absorptance \(a\), reflectance \(r\), and transmittance \(t\) is equal to \(1\): \(a + r + t = 1\). Therefore, \(a = 1 - \frac{1}{8} - \frac{1}{7} = 1 - \frac{15}{56} = \frac{41}{56}\).

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