Rankers Physics

Solids: Practice Problem & Solution

The bulk modulus of a spherical objects is '$B$'. If it is subjected to uniform pressure '$P$', the fractional decrease in radius is: (2017-Delhi)
$\frac{B}{3P}$
$\frac{3P}{B}$
$\frac{P}{3B}$
$\frac{P}{B}$

Solution Explained:

To solve this problem, we apply the core principles of Solids. Understanding the underlying formula is key to arriving at the correct answer below:

Bulk modulus $B = \frac{P}{\Delta V/V} \Rightarrow \frac{\Delta V}{V} = \frac{P}{B}$. For a sphere, $V = \frac{4}{3}\pi r^3$, so the fractional change in volume is $\frac{\Delta V}{V} = 3 \frac{\Delta r}{r}$. Therefore, $$\frac{\Delta r}{r} = \frac{1}{3} \frac{\Delta V}{V} = \frac{P}{3B}$$.

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