Logic Gates: Practice Problem & Solution
Boolean expression for the truth table given below is (A and B are inputs and Y is output) \[\begin{array}{|c|c|c|} \hline A & B & Y \\ \hline 0 & 0 & 1 \\ \hline 0 & 1 & 0 \\ \hline 1 & 0 & 0 \\ \hline 1 & 1 & 0 \\ \hline \end{array}\]
Solution Explained:
To solve this problem, we apply the core principles of Logic Gates. Understanding the underlying formula is key to arriving at the correct answer below:
The output \(Y\) is high only when both inputs \(A\) and \(B\) are low. This corresponds to a NOR gate, represented by the expression \(Y = \overline{A+B} = \overline{A} \cdot \overline{B}\).
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