Magnification of a Convex Lens – Rankers Physics

Refraction by Spherical Surfaces: Practice Problem & Solution

An object is mounted on a wall. Its image of equal size is to be obtained on a parallel wall with the help of a convex lens placed between these walls. The lens is kept at distance \(x\) in front of the second wall. The required focal length of the lens will be
\(\frac{x}{2}\)
\(\frac{x}{4}\)
Less than \(\frac{x}{4}\)
\(\frac{x}{4}\) but less than \(\frac{x}{2}\)

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Refraction by Spherical Surfaces. Understanding the underlying formula is key to arriving at the correct answer below:

For an image of equal size, the magnification is \(m = -1\), which means the image distance \(v = x\) is equal to the object distance \(u = x\). Using the lens formula: \(\frac{1}{f} = \frac{1}{v} + \frac{1}{u} = \frac{2}{x} ⇒ f = \frac{x}{2}\).

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