Rankers Physics

Total Internal Reflection: Practice Problem & Solution

Light enters at an angle of incidence in a transparent rod of refractive index n. For what value of the refractive index of the material of the rod, the light once entered into it will not leave it through its lateral face whatsoever be the value of angle of incidence: (1998)
$n > \sqrt{2}$
$1.0$
$1.3$
$1.4$

Solution Explained:

To solve this problem, we apply the core principles of Total Internal Reflection. Understanding the underlying formula is key to arriving at the correct answer below:

For light to undergo total internal reflection at the lateral surface regardless of the incidence angle at the entrance face, the critical angle must be less than or equal to $45^\circ$. Thus, $\sin \theta_c = \frac{1}{n} \le \sin(45^\circ) = \frac{1}{\sqrt{2}}$, which gives $n > \sqrt{2}$.

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