Spring Block System: Practice Problem & Solution

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Spring Block System. Understanding the underlying formula is key to arriving at the correct answer below:

The spring constant is \(k = \frac{F}{x} = \frac{10}{0.05} = 200\text{ N/m}\). The time period of the spring-mass system is \(T = 2pi \sqrt{\frac{m}{k}} = 2pi \sqrt{\frac{2}{200}} = 0.2pi \approx 0.628\text{ s}\).