A cubical vessel of height 1 m is full of water. The minimum work done in taking water-out from vessel will be
Solution:
As side length of cubical tank is 1 m. Volume is 1 m³. Volume of water in 1 m³ is 1000 lit and mass will be 1000 kg.
Height of center of mass of the tank will be 1/2 m.
Potential Energy = 1000 ×10 × 1/2 = 5000 J