Principle of Superposition, Interference and Beats - NEET Physics Questions
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Principle of Superposition, Interference and Beats

Question 1: moderate

Two waves of amplitude 2A and A of same frequency and velocity propogate in same direction with same phase. Then resultant amplitude is

1. 3A
2. √5A
3. √2A
4. A
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Resultant amplitude

\[ R= \sqrt{A^{2}+(2A)^{2}+ 2A.2A cos\theta} \]

As ΞΈ = 0ΒΊ

R= A+2A=3A

Question 2: moderate

Two waves of intensity I1 and I2 propagate in a medium in same direction. Then sum of maximum and minimum intensity is

1. \[ \left( \sqrt{I_{1}} -\sqrt{I_{2}}\right)^{2}\]
2. \[2 (I_{1}+I_{2}) \]
3. \[ (I_{1}+I_{2}) \]
4. \[ \left( \sqrt{I_{1}} +\sqrt{I_{2}}\right)^{2}\]
View Answer

\[ I _{max= }\left( \sqrt{I_{1}} +\sqrt{I_{2}}\right)^{2} \]

\[ I _{min = }\left( \sqrt{I_{1}} - \sqrt{I_{2}}\right)^{2} \]

\[ I _{max} + I _{min} = 2(I_{1} + I_{2})\]

Question 3: easy

Two waves of intensity ratio 9 : 1 produce interference then

\[ \frac{I _{max}}{I _{min} } = \]

1. 2:1
2. 4:1
3. 9:1
4. 10:8
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Question 4: moderate

A source of sound gives five beats per second when sounded with another source of frequency 100 s–1. The second harmonic of the source together with a source of frequency 205 s–1 gives five beats per second. What is the frequency of the source ?

1. 105 Hz
2. 205 Hz
3. 95 Hz
4. None of these
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Question 5: moderate

Ten tuning forks are arranged in increasing orderof frequency in such a way that any two nearest tuning forks produce 4 beats/sec. The highest frequency is twice of the lowest. Possible highest and the lowest frequencies are

1. 80 and 20
2. 100 and 50
3. 44 and 22
4. 72 and 36
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Question 6: moderate

Two coherent sources of different intensities send waves which interfere. The ratio of the maximum intensity to the minimum intensity is 25. The intensities are in the ratio

1. 25 : 1
2. 5:1
3. 9:4
4. 625:1
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