Dimensions - NEET Physics Questions
Question 31: easy

Which of the following dimensions will be the same as that of time?

[1996]

1. \(L/R\)
2. \(C/L\)
3. \(LC\)
4. \(R/L\)
View Answer

The ratio \(L/R\) has the dimensions of time, \(T\).

Question 32: easy

Which of the following is a dimensional constant?

[1995]

1. Relative density
2. Gravitational constant
3. Refractive index
4. Poisson ratio
View Answer

A dimensional constant is a physical constant with dimensions. The Gravitational constant \(G\) is a dimensional constant with dimensions \(M^{-1}L^3T^{-2}\).

Question 33: easy

The dimensions of \(RC\) is:

[1995]

1. Square of time
2. Square of inverse time
3. Time
4. Inverse time
View Answer

The product \(RC\) represents the time constant of an \(RC\) circuit, and its dimension is time, \(T\).

Question 34: easy

Which of the following has the dimensions of pressure?

[1994,90]

1. \(MLT^{-2}\)
2. \(ML^{-1}T^{-2}\)
3. \(ML^{-2}T^{-2}\)
4. \(M^{-1}L^{-1}\)
View Answer

Pressure is defined as Force per unit Area. Its dimensions are \(MLT^{-2} / L^2 = ML^{-1}T^{-2}\).

Question 35: easy

Dimensional formula of self inductance is:

[1989]

1. \(MLT^{-2}A^{-2}\)
2. \(ML^2T^{-1}A^{-2}\)
3. \(ML^2T^{-2}A^{-2}\)
4. \(ML^2T^2A^{-1}\)
View Answer

The energy stored in an inductor is \(U = \frac{1}{2}LI^2\). Therefore, the dimensions of self-inductance \(L\) are \(U/I^2 = [ML^2T^{-2}]/[A^2] = [ML^2T^{-2}A^{-2}]\).

Question 36: easy

The dimensional formula of torque is:

[1989]

1. \(ML^2T^{-2}\)
2. \(MLT^{-2}\)
3. \(ML^{-1}T^{-2}\)
4. \(ML^{-2}T^{-2}\)
View Answer

Torque is calculated as Force \(\times\) perpendicular distance. So its dimensions are \([MLT^{-2}] \times [L] = [ML^2T^{-2}]\).

Question 37: easy

If \(C\) and \(R\) denote capacitance and resistance, the dimensional formula of \(CR\) is:

[1988]

1. \(M^0L^0T^1\)
2. \(M^0L^0T^0\)
3. \(M^0L^0T^{-1}\)
4. Not expressible in terms of MLT
View Answer

The product \(CR\) is the time constant of an RC circuit. Its dimension is time, \(T\), which can be written as \(M^0L^0T^1\).

Question 38: easy

The dimensional formula of angular momentum is:

[1988]

1. \(ML^2T^{-2}\)
2. \(ML^{-2}T^{-1}\)
3. \(MLT^{-1}\)
4. \(ML^2T^{-1}\)
View Answer

Angular momentum is defined as \(L = r \times p\), where \(r\) is distance and \(p\) is linear momentum. Its dimensions are \([L][MLT^{-1}] = [ML^2T^{-1}]\).

Question 39: easy

The dimension of Planck constant equals to that of:

[2001]

1. Energy
2. Momentum
3. Angular momentum
4. Power
View Answer

Planck's constant \(h\) has dimensions \(ML^2T^{-1}\). Angular momentum also has dimensions \(ML^2T^{-1}\).

Question 40: easy

Turpentine oil is flowing through a tube of length (l) and radius (r). The pressure difference between the two ends of the tube is (P). The viscosity of oil is given by \(\eta = \frac{P(r^2 – x^2)}{4vl}\) where (v) is the velocity of oil at a distance (x) from the axis of the tube. The dimensions of (eta) are:

[1993]

1. \(M^1L^0T^0\)
2. \(MLT^{-1}\)
3. \(ML^{-2}T^{-1}\)
4. \(ML^{-1}T^{-1}\)
View Answer

\([P] = [ML^{-1}T^{-2}]). ([r^2 - x^2] = [L^2]\). \([v] = [LT^{-1}]\). \([l] = [L]\). \([\eta] = \frac{[ML^{-1}T^{-2}][L^2]}{[LT^{-1}][L]} = \frac{[MLT^{-2}]}{[L^2T^{-1}]} = [ML^{-1}T^{-1}]\).