A body of weight W1 is suspended from the ceiling of a room through a chain of weight W2. The ceiling pulls the chain by a force
Total weight of chain + block system is W1 +W2.
Block A of mass 4 kg is to be kept at rest against a smooth vertical wall by applying a force F as shown in figure. The force required is (g = 10 m/s²)
In the given arrangement, the normal force applied by block on the ground is
The value of \( \frac{T_{3}}{T_{1}} \) is
\[ \]
The ratio of tension T1 and T2 is (strings are massless)
A man of mass m is standing on a board and pulling the board of mass m up with force F by the pulley system as shown. Normal reaction between man and board is
As the person is in equilibrium net force acting on it should be zero,
so, mg = N + F
⇒ N = mg - F
In the arrangement shown, the normal reaction between the block A and ground is:
Weight of block = N.
Weight of block = N.
Tension in the string = Weight of = 20 N.
Normal reaction on , Weight of – Tension = N.
In translatory equilibrium
In translational equilibrium the net force acting on the object is zero. so the object moves with constant velocity.
A body in equilibrium will not have :
For a body in equilibrium, the net external force acting on it is zero. According to Newton's second law, \(F_{\\text{net}} = ma = 0\), which means the acceleration of the body must be zero.
A body is said to be in mechanical equilibrium if
For complete mechanical equilibrium, a body must be in both translational equilibrium (net external force is zero) and rotational equilibrium (net external torque is zero).
