Equilibrium based Questions

Question 1:

A body of weight W1 is suspended from the ceiling of a room through a chain of weight W2. The ceiling pulls the chain by a force

1. W1

2. W2

3. (W1+W2)/2

4. W1+W2

View Answer

Total weight of chain + block system is W1 +W2.

Question 2:

Block A of mass 4 kg is to be kept at rest against a smooth vertical wall by applying a force F as shown in figure. The force required is (g = 10 m/s²)

equilibrium based question in laws of motion neet physics

1. 40√2 N

2. 20√2 N

3. 10√2 N

4. 15√2 N

View Answer

equilibrium based question in laws of motion neet physics

For Equilibrium, F cos ( 45°) = 40

so, F = 40√2 N

Question 3:

In the given arrangement, the normal force applied by block on the ground is

laws of motion neet physics questions

1. mg

2. mg – Fcosθ

3. mg + Fcosθ

4. Fcosθ

View Answer

For Equilibrium in vertical direction

F cos θ + N = mg

or N = mg - F cosθ

Question 4:

The value of $ \frac{T_{3}}{T_{1}} $ is

\[ \]

1. 1

2. 2

3. 3

4. 3/2

View Answer

As the arrangement is in equilibrium T3= 150 N and T1 = 50 N

so T3/T1=3

Question 5:

The ratio of tension T1 and T2 is (strings are massless)

1. 7 : 2

2. 7 : 5

3. 5 : 2

4. 2 : 7

View Answer

For Equilibrium Condition,

T1 = 70 N and T2 = 50 N so, T1: T2 = 7 : 5 neet equilibrium question

Question 6:

A man of mass m is standing on a board and pulling the board of mass m up with force F by the pulley system as shown. Normal reaction between man and board is

neet question for equilibrium NLM

1. mg – F

2. mg + F

3. (m + M) g + F

4. (m – M)g – F

View Answer

As the person is in equilibrium net force acting on it should be zero,

so, mg = N + F

⇒ N = mg - F

Question 7:

In the arrangement shown, the normal reaction between the block A and ground is:

1. 10 N

2. 20 N

3. 30 N

4. 40 N

View Answer

Weight of block $A$ = $4 \times 10 = 40$ N.

Weight of block $B$ = $2 \times 10 = 20$ N.

Tension in the string $T$ = Weight of $B$ = 20 N.

Normal reaction on $A$ , $N =$ Weight of $A$ – Tension $T$ = $40 - 20 = 20$ N.

Question 8:

In translatory equilibrium

1. The net external force acting on particle is zero

2. The net external force acting on particle is constant (non-zero)

3. Particle is always at rest

4. Velocity of particle changes linearly with time

View Answer

In translational equilibrium the net force acting on the object is zero. so the object moves with constant velocity.