A particle is thrown upwards from ground. It experience a constant air resistance force which can produce a retardation of 2 m/sĀ². The ratio of time of ascent to the time of descent is : [g = 10 m/sĀ²]
Effective accelerations:
- Ascent: \( a_{\text{eff}} = g + a = 10 + 2 = 12 \, \text{m/s}^2 \)
- Descent: \( a'_{\text{eff}} = g - a = 10 - 2 = 8 \, \text{m/s}^2 \)
Ratio of times:
\[
\frac{t_a}{t_d} = \sqrt{\frac{a'_{\text{eff}}}{a_{\text{eff}}}} = \sqrt{\frac{8}{12}} = \sqrt{\frac{2}{3}}
\]
The ratio of time of ascent to time of descent is ā(2/3).