The given graph shows the variation of velocity with which one of the graph given below correctly represents the variation of acceleration with displacement :
Graphs of Motion
The displacement-time graph of two moving particles A and B respectively make angles of 30° and 45° with the x-axis respectively. The ratio of their velocities is
Solution:
Slope of displacement time graph represents velocity.
VA= tan 30 0
VB= tan 45 0
So, VA/VB=tan 30 0/tan 45 0= 1/√3
A body is travelling in a straight line with a uniformly increasing speed. Which one of the plot represents the change in distance (s) travelled with time (t)?
Solution:
\[ s= \frac{1}{2}at^{2}\]
As s is proportional to square of t. s-t graph is a parabola.
A particle is thrown upwards, then correct v-t graph will be
Solution:
Slope of v-t graph represent acceleration. when object is thrown upward its acceleration is -g for the entire journey. So, slope is -g.
A body starts from rest and moves with uniform acceleration. Which of the following graphs represents it motion?
Solution:
\[ v = u + at ; as, u = 0 ; v = at\]
As, v is proportional to t ; graph of v-t is a straight line.
If the figure below represents a parabola, identify the physical quantities representing Y and X for constant acceleration
Solution:
\[ S= \frac{1}{2}at^{2}\]
As, S is proportional to t graph is a parabola
The v-t graph for a particle is as shown. The distance travelled in the first four second is
Solution:
Area bounded by v-t graph represents displacement. Here.
Area = (1/2)×4×8= 16
So, Distance travelled is 16 m.
A particle starts form rest. Its acceleration (a) versus time (t) is as shown in the figure. The maximum speed of the particle will be
Solution:
Area of acceleration time graph represents change in velocity. As acceleration is always positive speed is always increasing.
Area = (1/2)× 10× 11 = 55
So, max. speed of 55 m/s
A particle is thrown vertically upwards with a velocity ν. It returns to the ground in time T. Which of the following graphs correctly represents the motion?
Solution:
Graph of velocity time graph represents acceleration. During the entire journey acceleration is -g. so slope is negative.
A rocket is fired upwards. Its velocity versus time graph is shown in figure. The maximum height reached by the rocket is :
No solution provided for this question.