Electric Field Lines – Rankers Physics
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Electric Field Lines

Question 1:

Find out correct relation between electric field intensity EA & EB present at two points in an electric field shown in the figure.

\[ E_{A}=E_{B}\]
\[ E_{A}>E_{B}\]
\[ E_{A}< E_{B}\]
Data insufficient
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Solution:

Distance between electric field lines represents magnitude of electric field lines. Large is the separation between electric field line lesser is electric field. so ,

\[ E_{A}< E_{B}\]

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Question 2:

The figure shows the electric field lines in the vicinity of two point charges . Which one of the following statements concerning this situation is true ?

q1 is negative and q2 is positive
The magnitude of the ratio (q2/q1) is less than one
Both q1 and q2 have the same sign of charge
The electric field is strongest midway between the charges .
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Solution:

Number of electric field lines coming out of a charge represents magnitude of charge. Here number of field line coming out of q1 is more than that of q2 so, |q2/q1 |<1.

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Question 3:

Three positive charges of equal value q are placed at the vertices of an equilateral triangle . The resulting lines of force should be sketched as in

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Solution:

Option 1 is wrong as electric field lines will emerge out of +ve charge and should submerge only at -ve charge.

Option 2 is wrong as electric field lines can not be circular loop.

Option 3 is correct.

Option 4 is wrong because it is representing equipotential surface not field lines

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Question 4:

For the figure shown, what is the ratio of the charges q2/q1, where the figure shown has a representation of the field lines in the space near the charges

–3/2
–2/3
2/3
3/2
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Solution:

Number of Electric Field line is proportional to amount of charge. so,

\[ \frac{Q_{2}}{Q_{1}}=\frac{-6}{9}=\frac{-2}{3} \]

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Question 5:

Which of the following configurations of electric lines of force is not possible ?

both (2) and (3)
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Solution:

Option 2 is wrong because electric field lines emerge out of +ve charge and submerge into -ve charge.

In option 3 number of electric field lines is proportional to amount of charge. From +5C charge 6 field lines are emerging out where as from 1C charge only one electric field line is present.

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Question 6:

The figure below shows the electric field lines due to two positive charges. The magnitudes \(E_{A},E_{B} and E_{C}\) of the electric fields at points A, B, and C respectively are related as :

 

\[E_{A}>E_{B}>E_{C}\]
\[E_{B}>E_{A}>E_{C}\]
\[E_{A}=E_{B}>E_{C}\]
\[E_{A}>E_{B}=E_{C}\]
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Solution:

Number of Electric field line in space represents electric field intensity. As number of field line is maximum at A followed by B then at C. so, \(E_{A}>E_{B}>E_{C}\)

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