(2001)
Solution:
Efficiency $\eta = \frac{\text{Work output}}{\text{Work input}} = \frac{mgh}{F \cdot d} = \frac{75 \times 10 \times 3}{250 \times 12} = \frac{3}{4} = 75\%$.
250 N force is required to raise 75 kg mass from a pulley. If rope is pulled 12 m then the load is lifted to 3 m, the efficiency of pulley system will be:
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