Intensity Ratio of Two Waves – Rankers Physics
Topic: Waves
Subtopic: Waves and its Characteristics

Intensity Ratio of Two Waves

Two waves represented by the following equations are travelling in the same medium: \(y_1 = 5 \sin 2\pi(75t - 0.25x)\) and \(y_2 = 10 \sin 2\pi(150t - 0.50x)\). The intensity ratio \(I_1/I_2\) of the two waves is:
1 : 2
1 : 4
1 : 8
1 : 16

Solution:

The intensity of a wave is proportional to the square of its amplitude and frequency, \(I \propto A^2 f^2\). Substituting \(A_1=5, f_1=75\) and \(A_2=10, f_2=150\) gives \(\frac{I_1}{I_2} = \left(\frac{5}{10}\right)^2 \left(\frac{75}{150}\right)^2 = \frac{1}{16}\).

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