Solution:
Wavelength \(\lambda = \frac{v}{f} = \frac{330}{500} = 0.66\text{ m}\). Path difference \(\Delta x = \frac{\lambda}{2\pi} \Delta \phi = \frac{0.66}{2\pi} \left(\frac{\pi}{6}\right) = 0.055\text{ m}\).
A progressive wave of frequency \(500\text{ Hz}\) is travelling with a speed of \(330\text{ m/s}\) in air. The distance between the two points which have a phase difference \(30^{circ}\) is
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