Solution:
The time period is \(T = \frac{2\pi}{\pi/2} = 4\text{ s}\). The interval \(t = 3\text{ s}\) corresponds to \(\frac{3T}{4}\). In each quarter cycle, the distance covered is \(a\), so total distance is \(3a\).
A particle moves according to equation, \(x = a \cos\frac{\pi t}{2}\). The distance covered by it in the time interval between \(t = 0\) to \(t = 3\text{ s}\) is
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