Solution:
The expression can be written as \(y = P \sin \left( \frac{2\pi Q}{\lambda}t - \frac{2\pi}{\lambda}x \right)\). The angular frequency is \(\omega = \frac{2\pi Q}{\lambda}\). Thus, the frequency is \(f = \frac{\omega}{2\pi} = \frac{Q}{\lambda}\).
Leave a Reply