Solution:
The frequency of the \(1^{\text{st}}\) overtone (third harmonic) of a closed organ pipe is given by \(f = \frac{3v}{4L}\). Given \(f = 480\text{ Hz}\) and \(v = 320\text{ m/s}\), we have \(480 = \frac{3 \times 320}{4L} ⇒ L = \frac{960}{1920} = 0.5\text{ m} = 50\text{ cm}\).
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