YDSE Intensity and Energy Conservation – Rankers Physics
Topic: Wave Optics
Subtopic: Young's Double Slit Experiment

YDSE Intensity and Energy Conservation

Assertion (A): In Young's double slit experiment if intensity of each source is \(I_0\) then minimum and maximum intensity is zero and \(4I_0\) respectively.
Reason (R): In Young's double slit experiment energy conservation is not followed.
 
Both (A) & (R) are true and the (R) is the correct explanation of the (A)
Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
(A) is true but (R) is false
Both (A) and (R) are false

Solution:

In YDSE with coherent sources of intensity (I_0) each, \(I_{\text{min}} = (\sqrt{I_0} - \sqrt{I_0})^2 = 0\) and \(I_{\text{max}} = (\sqrt{I_0} + \sqrt{I_0})^2 = 4I_0\). Thus, A is true. Energy is conserved in interference; it's redistributed, not destroyed. Thus, R is false.

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