Brewster’s Angle for Denser Medium – Rankers Physics
Topic: Wave Optics
Subtopic: Miscellaneous

Brewster’s Angle for Denser Medium

If light is entering from air to a medium and \( \theta_B \) represents Brewster's angle for interface of the two medium, then
\( \theta_B = 90^\circ \)
\( 0^\circ < \theta_B < 90^\circ \)
\( 45^\circ < \theta_B < 90^\circ \)
\( 30^\circ < \theta_B < 60^\circ \)

Solution:

Brewster's law states that \( \tan\theta_B = \mu \). Since the light enters from air to a denser medium, \( \mu > 1 \), which means \( \tan\theta_B > 1 \) and hence \( 45^\circ < \theta_B < 90^\circ \).

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