Brewster’s Angle Range – Rankers Physics
Topic: Wave Optics
Subtopic: Miscellaneous

Brewster’s Angle Range

The Brewster's angle \(\theta\) for an air-medium interface should be
0° < \(\theta\) < 30°
30° < \(\theta\) < 45°
45° < \(\theta\) < 90°
\(\theta\) = 90°

Solution:

Brewster's law states \(tan\theta = \mu\). Since the refractive index of any medium with respect to air is \(\mu > 1\), we have \(tan\theta > 1 \implies \theta > 45^\circ\). Thus, \(45^\circ < \theta < 90^\circ\).

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