Solution:
Mean value is \(42\text{ N}\). Absolute errors are \(|40-42|=2\), \(|42-42|=0\), \(|44-42|=2\), \(|39-42|=3\), \(|45-42|=3\). Mean absolute error is \(\frac{2+0+2+3+3}{5} = 2\text{ N}\).
Weight measured by a spring balance gives following readings: 40 N, 42 N, 44 N, 39 N, 45 N. What is the mean absolute error of the observations?
Leave a Reply