[2008]
Solution:
Volume of a sphere \(V = \frac{4}{3}pi r^3\). The percentage error in volume is (3) times the percentage error in radius. Given \(\delta r/r \times 100 % = 2 % \). So, Percentage error in \(V = 3 \times 2 % = 6% \).
If the error in the measurement of radius of a sphere is 2%, then the error in the determination of volume of the sphere will be:
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